三线摆测转动惯量数据处理
5.1 各物理量不确定度的估算
M=520.33g,∆M =0. 05g ,U M =∆M
=0. 05g
=0. 029g
,
=44.18mm ,S =0.012mm ,∆m =0.02mm ,
22u B =∆m =0.012mm , 22S +u B (0. 012) +(0. 012) u ==mm =0.017mm ,
∆m u B ==S 0.012mm , =114.21mm, =0.006mm,
u b =22(0. 006) +(0. 012) =mm=0.013mm,
∆m u B ==0. 0290= 50.12 cm,S 0=0.011cm ,∆m =0.05cm ,cm , S +u B 22
u 0=S 0+u B 22(0. 011) +(0. 029) =cm = 0.031cm,
∆m u B ==0. 0290= 87.49 s ,S 0=0.016s,∆m =0.05s ,3s ,
22(0. 016) +(0. 029) = =s =0.033s,
∆m u B ==0. 0291= 51.00cm,S 1=0.018cm, ∆m =0.05cm , 3cm , 22u t 0S 0+u B 22
22(0. 018) +(0. 029) ==cm = 0.034cm,
∆m u B ==0. 0291=74.51s, S 1=0.020s, ∆m =0.05s , s , u H 1S 1+u B 22
=
5.2转动惯量的计算
5.2.1 悬盘转动惯量的计算(计算时把单位都化为千克、米、秒制) u t 1S t 1+u B 2222(0. 020) +(0. 029) = s =0.035s, I 0=mgab 2T 012π2H 0 0. 299kg ⨯9. 789ms -2⨯4. 418⨯10-2m ⨯11. 421⨯10-2m 87. 492⨯(s ) 25012⨯(3. 142) ⨯0. 5012m =
-42=7.616⨯10(kg. m)
u I 0=I 0u H 022u T 02u a 2u b 2() +() +() +() 00-42 = 7.616⨯10(kg. m)×
-42=0.0054⨯10(kg. m)
5.2.2载物转动惯量的计算 (0. 01720. 01320. 03120. 0332) +() +() +(2) 44. 18114. 2150. 1287. 49
I 1=(M +m ) gab 2T 112π2H 1
0. 81933kg ⨯9. 789ms -2⨯4. 418⨯10-2m ⨯11. 421⨯10-2m 74. 562⨯(s ) 25012⨯(3. 142) ⨯0. 5100m =
32=1.4897⨯10-(kg. m)
u I 1=I 1⨯(u H 2u T u a 2u u ) +(b ) 2+(1) 2+(1) 2+(M ) 2
11M +m 2 =1.4897⨯10-(kg. m)×
42=0.018⨯10-(kg. m)
5.2.3 不规则无题转动惯量的计算 3(0. 01720. 01320. 03420. 03520. 0292) +() +() +(2) +() 44. 18114. 2151. 0074. 51819. 33
I =I 1-I 0=1.4897⨯10-3- 7.616⨯10-4=7.281⨯10-4(kg. m2)
22u I =u I 0+u I 1=(0. 0054) +(0. 018) =0.019⨯10-4(kg. m2) 22
5.3 实验结果
I =(7.38±0.02)⨯10-4(kg. m2) (P=0.683)